Python Data Structures

Unpacking a list

Use *:

>>> l = list(range(5))
>>> a,b,*c=l
>>> print(a)
0
>>> print(b)
1
>>> print(c)
[2, 3, 4]

>>> l = ['foo', 'bar', *list(range(3)), 'fax']
>>> l
['foo', 'bar', 0, 1, 2, 'fax']

Iterate over a sequence of tuples or list

a. Use itertools.chain:

a = list(range(5))
b = ('foo','bar','fax')
for v in itertools.chain(a,b):
    print(v)

a. Create a new list with +, converting the tuple to list:

a = list(range(5))
b = ('foo','bar','fax')
for v in a + list(b):
    print(v)

Either way it will print:

0
1
2
3
4
foo
bar
fax